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Repair and reformation of LED rechargeable lithium battery flashlight

by:dcfpower     2021-03-16
A YG-859LED rechargeable flashlight, after using it for a period of time, has the following malfunctions: After charging for a whole night, the brightness of the LED light drops rapidly after only a few minutes. So, disassemble the flashlight for inspection. For the convenience of maintenance, it will be drawn according to the circuit principle of physical survey and mapping for reference during maintenance. The working principle of this rechargeable LED flashlight is relatively simple, with a current limiting and charge discharge circuit composed of C1 and R. When the upper end of the 220V AC power supply is positive, the current flows through C1,→D1→slide switch→battery positive→battery negative→D4 back to the negative end of the 220V AC power supply. When the lower end of the 220V AC power supply is positive, the current flows through D3→slide switch, battery positive→battery negative→D2→C1→back to the negative terminal of the 220V AC power supply. At the same time, the other way comes out from the positive terminal of the battery, and goes back to the negative terminal of the 220V AC power supply through the charging indicator LED D5→330Ω current limiting resistor→C1→C1. When the sliding switch is pushed to the lighting position I, the white light LEDs 1, 3, 5, 7, and 9 will light up. When the sliding switch is pushed to the lighting position II, in addition to the white light LED 1, 3, 5, 7, and 9 lighting, the white light LED 2, 4, 6, and 8 also emit light at the same time. Check all the components in the flashlight and found that the Φ3 red charging indicator LED D5 has reverse leakage phenomenon. After replacing it with a new one, charging for 12 hours, the fault remains. When such failures occur, the problem is generally with lead storage batteries, because manufacturers use mini-maintenance-free lead storage batteries for flashlights of this price in order to reduce manufacturing costs. This type of battery has a short life span, and most of them use less than one and a half years. It is broken, it is caused by the decrease of battery capacity due to the evaporation of battery electrolyte. The repair method is to replace a new battery or repair the battery. Since there is no supply of such batteries in the market, and the methods introduced in the past have been repaired to no effect, I am going to throw away the flashlight. I just remembered that I had 4 2300mAh AA rechargeable Ni-MH rechargeable batteries that were eliminated by digital cameras. These 4 batteries have been out of service for a long time, causing aging to varying degrees. After being sealed and heated in a pressure cooker according to the method introduced, it has some effects, but it is still not good for digital cameras. Based on the principle of waste utilization, the four nickel-hydrogen batteries are welded together in series to form a nickel-hydrogen battery pack, the original battery is removed, and the nickel-hydrogen battery pack is connected to the original battery position. Open the slide switch to test, the flashlight resumes normal work. It can be seen from the above figure that the flashlight is a storage battery and charging is controlled by a sliding switch. For safety reasons, do not try to flip the light switch when the flashlight is charging. The size of the battery charging current is determined by the current-limiting capacitor C. You can refer to the following formula: Cu003d14.5I. The unit of C is μF, and I is A. The derivation steps of this formula are as follows: Suppose the capacitive reactance of the capacitor C in a 50Hz AC circuit is Xc-1/2π? Cu003d1/2×3.14x50xC, then Iu003dU/Xcu003d220x2π?Cu003d220x2×3.14 ×50C, so Cu003dI/220×314. Here, the unit of C is F (Farad), and I is A (ampere), and the international unit is used. If the unit of C is changed to μF at this time, to keep the equation unchanged, the right side of the equation needs to be multiplied by 106. Then C≈14.471 is introduced. It can be used as Cu003d14.5I. In this circuit, Cu003d1μF, and Cu003d14.5I can be charged according to the formula. The total current Iu003d69mA passed in the charging circuit is basically consistent with the actual measured 69.7mA. Even ignoring the current consumed by D5, based on the full battery capacity of 2300mAh, it will take about 33 hours to charge before the battery can be fully charged. However, this is enough. After observation, after fully charged, it was used intermittently and there was no problem for a month. u003c/pu003e
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